Proot 3 V I Cos Phi

Current and multiply with 175.

Proot 3 v i cos phi. With alternating voltages the apparent power s in va of an inductive load is stronger than the active power p in w which is actually used by the load. Pvicos phi for 3 phase proot 3 vicos pji. Using impedence triangle we can find out the value of power factor.

Now for minimizing losses across the line which is proportional to i2r it is always intended to minimize the curren. Ans is right but required. If i do the simple calculation i p root 3 u cos phi i can not find the value of the same current.

What is the difference between a mitiplus 12200080 and a mutiplus of 24200050 apart the voltage one of which is 12 v and the other 24 v and the battery charging current which one is 80a and the other 50 a. Spherical coordinates can be a little challenging to understand at first. Cos f ps examples.

The cos phi is a power factor. It is the ratio between active power and apparent power. Please help members by posting answers for below questions.

What do you mean by every ic 74 first digitwhy are you using this nowhy not using another no. V 400 volt. V 110 volt f 60 hz i 33 a cos phi 075 p.

Putting the value of v p cosphi. P v i cos phi p 110 33 075 p 27225 watt3. Is this answer correct.

The electric motor has specification. How many kilo watt power of electric that used the motorcatat. Post new answer view all answers.

Power factor cos phi resistance r impedence z for pure resistive ac. The cos phi equals active power p divided by the apparent power s. It is equal of cos phi where phi is the phase difference between the instantneous current and voltage in the ac.

Circuit z r cos phi 1. Find out current ie i after. P root 3 vi cos phi.

Ptp1p2p3 p1vi1cosf1 i1p1vcosf1 same thing for each phase vp1icosf1. Voltage 400 volt single phase frequency 70 hz current 10 ampere and cos phi 065. And you will get required.